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\[-b \pm \sqrt{b^2-4ac/2a}\]
no \[\frac{ -b \pm \sqrt{b^{2}-4*a*c} }{2*a }\] what is a= b= c=
you cant read them
ax^2+bx+c thats the general form
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2x^2 + 8x + 3 ax^2 + bx + c does that help ?
i knwo how to do the quad. form
what are the values for a,b,c?
\[\frac{ -8\pm \sqrt{8^2-4(2)(3)} }{ 2(2) }\]
now can i do the problem
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thats all you need just multiply then numbers
\[\frac{ -8\pm \sqrt{40} }{ 4 }\]
can you simplify
i dont under why -8 is either 4 or 8 negative
why isnt it -2
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