Question

find the other zeros of f(x) = x^3 + 5x^2 - 18x -72

Answer 1

one of the zeros is 4

Answer 2

x^3+5*x^2-18*x-72
x^3+5*x^2-18*x-72 =

= (x+6)*(x+3)*(x-4)
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'x' values that are zeros of the polynomial:
Real solutions:
Root 1: -6
Root 2: -3
Root 3: 4
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Answer 3

wait how did u get that

Answer 4

what do you mean??
its step by step...