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Physics 14 Online
OpenStudy (anonymous):

A rod with length l and mass m is standing at first perpendicular on a frictionless table, then he begins to fall. What is the velocity of the center of mass in terms of its position?

OpenStudy (anonymous):

I thought I could work this out using the energies. mgH=mgh+0.5mv^2+0.5*I*w^2 v is the speed of the center of mass but I have no clue how I can express w (omega) in terms of v.

OpenStudy (anonymous):

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