A rod with length l and mass m is standing at first perpendicular on a frictionless table, then he begins to fall.
What is the velocity of the center of mass in terms of its position?

Question

A rod with length l and mass m is standing at first perpendicular on a frictionless table, then he begins to fall.
What is the velocity of the center of mass in terms of its position?

anonymous · Answer

I thought I could work this out using the energies. 
mgH=mgh+0.5mv^2+0.5*I*w^2

v is the speed of the center of mass but I have no clue how I can express w (omega) in terms of v.

anonymous · Answer

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