Question

IM SOO HAPPY I THINK I UNDERSTAND THIS!!!Graph the two equations to solve the system. What is the solution?
1/2 x - 2y = 4 and 4y - x = -8

(-2, 0)
no solution
(3, 4)
infinitely many solutions

the answer is (-2,0) right?

Answer 1

Just check it, substitute the -2 for x and 0 for and see if it works. I personally don't think it will.

Answer 2

i graphed it

Answer 3

rewrite the lines lin point, slope form

subtract 2x to both sides add x to both sides
-2y = - 1/2 x + 4 4y = x - 8

divide by -2 divide by 4

y = -1/4x -2 y = -1/4x - 2

what can you make of this...

Answer 4

uuuh ...?

Answer 5

am i right?

Answer 6

(1/2)(-2) - 2 (0) = 4 ??????????

Answer 7

Does -1 - 0 = 4 ?

Answer 8

no...

Answer 9

That is what you proposed solution results for the first equation.

Answer 10

look i graphed it and they intercepted at (-2,0) and that is a choice

Answer 11

Well I guess we can't argue with that! If they intersect then that is the answer. Are you sure you graphed them properly?

Answer 12

yes i checked them

Answer 13

Did they actually intersect or were they the same line (coincidence)

Answer 14

no trhey intersected

Answer 15

From what I can tell they are two lines with the same slope intercept equation.
y=(1/4)x - 2

Answer 16

They are the same line and the are coincidence, with infinite points of coincidence with infinitely number of solutions.

Answer 17

no i mean they did exactly intercect at -2,0

Answer 18

Well let me double check......the first equation is (1/2)x -2y = 4, now subtract (1/2)x from both sides getting -2y= (-1/2)x + 4 Now divide both sides by -2 getting:
y = (1/4)x - 2 Do you agree that the first line is (in slope intercept form) y= (1/4)x -2?

Answer 19

i think so

Answer 20

Now lets take the second equation which is: 4y - x = -8 lets add x to both sides getting
4y = x - 8 Now divide thru by 4 getting: y=(1/4)x - 2 Do you see that they are identical?? One line is laying on top of the other, they are the same there is infinitely manty solutions.

Answer 21

Can you use the "Draw" function and sketch your graph so we can look at it?