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y=5x^2+7x-5 Use the quadratic formula to find any x-intercept on the graph of the equation.
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the quadratic formula is use for quadratics \[ax^2 + bx + c = 0\] \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] in your question a the x-intecepts are where y = 0 so you would have a = 5, b = 7 and c = -5 just substitute and evaluate.
how would i do that
can you help me with that
|dw:1354927892718:dw|
do order of operation
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is that the x intercept
yes
|dw:1354928089190:dw|what number is under the square root sign
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