Hiram raises earthworms. In a square of compost 4 ft by 4 ft, he can have 1,000 earthworms. How many earthworms can he have if his square of compost has a side length that is 7 times longer? Help please?

Question

anonymous · Answer

hiram has a lot of worms
4 x 4 = 1,000
4 x 4(7) =7 boxes at 4x4 or 7,000 worms

anonymous · Answer

above, 4 x 4 means 4 by 4, not 4 * 4, that looks confusing.

anonymous · Answer

answer choices are 49,000 or 196,000

anonymous · Answer

if the side length become 7 times ,then  it should be
4(7) x 4(7)

anonymous · Answer

=49(1000)=49000

anonymous · Answer

if both side lengths are increased by 7, he would have 7*7 more worms, or 49,00

anonymous · Answer

im confused :(

anonymous · Answer

no of earthworm is proportional to the area of the plot
1000 ~ 4*4                              (let ~ stand for proportional)
now sides are 7 times longer
(7*4)*(7*4) =7*7*(4*4)
we already know (4*4)~1000
 so  =7*7*1000=49000

anonymous · Answer

did u get that ?

anonymous · Answer

yes thanx!:) so much

anonymous · Answer

:)