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solve 3^x+1=1/27
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3^x = (1/27) - 1
3^x = -26/27
I think he means \[3^{x+1} = {1 \over 27} \] \[3^{x+1} = {3^{-3}} \] so x+ 1 = -3 x = -4
You can also take log(base 3) from each side and solve.
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