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sinx(cscx)/tanx
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what about it
lol pete :o
For this problem, to simplify, you'll want to change everything to sines and cosines. So you'll need to remember a few identities :)\\[\large \csc x=\frac{1}{\sin x}, \qquad \tan x=\frac{\sin x}{\cos x}\]
I got to 1*cosx*sin^2s/sinx
\[\huge \frac{\sin x(\csc x)}{\tan x} \qquad \rightarrow \qquad \frac{\sin x\left(\frac{1}{\sin x}\right)}{\left(\frac{\sin x}{\cos x}\right)}\]
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\[\huge \frac{1}{\left(\frac{\sin x}{\cos x}\right)} \qquad \rightarrow \qquad \frac{\cos x}{\sin x}\]
Hmm I think you get something like that.
Oh jesus that was simple, I overlooked the sin*1/sin cancellation. thanks!
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