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The function f is given by f (x) = sqrt 1n (x - 2). Find the domain of the function
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domain of f=\[{x:x \in R , x >2}\]
no that's what i thought too, but i have the actual answer and reason though but i dont get it ln (x – 2) >= 0 since we need to find its square root x – 2 >= 1 x >= 3
i don't thing that u shaould be \[x-2\neq 0\]
becaous undefind ln(0)
yeah exactly, i guess i'll ask my teacher. anyway thanks
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