Question

How do I do quadratic formula on
2x^2 – 7x - 3 = 0

Answer 1

Plug a = 2, b = -7 and c = -3 into the formula below and simplify


\[\Large x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]


\[\Large x = \frac{-(-7)\pm\sqrt{(-7)^2-4(2)(-3)}}{2(2)}\]


\[\Large x = \frac{7\pm\sqrt{49-(-24)}}{4}\]


I'll let you finish