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Please I really need help with this one.Find an equation of the circle passing through (6, 7) and tangent to the line y = 2x + 1 at (5, 11). Write your answer in standard form.
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So to find the tangent line, you have to derive. You understand this part right?
And then to derive...y'=2
When you derive, you get the slope...So the slope of your tangent line is 2.
So now you put this into point slope form y-7=2(x-6)
And then to put it into standard form you just do some algebra: y=2x-12+7-->2x-5
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what would I get
y=2x-5
|dw:1355017036124:dw|
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