A soccer ball is given a kick – it ends up going with an initial velocity of 28 m/s at an angle of 35 above the horizontal. Neglecting air friction, (a) how long was the ball in the air, and (b) what is the horizontal displacement of the kick?

Question

anonymous · Answer

Are you familiar with components? If you do, 
$S_y=u_y t +\frac{1}{2} a_y t^2$
as $S_y=0$, i.e. it goes up and then back down to the ground,
$u_y=28 \sin 35^o ms^{-1}$, $a_y =-9.8$
plug it all in to get t.
$S_x=u_x t +\frac{1}{2} a_x t^2$
where $a_x =0$, t is found from the first, and $u_x =28 \cos 35^o ms^{-1}$
plug it all in  to get $S_x$

do you need further help?