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My answer is A Simplify i18 Answers: 1 -1 -i i
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do u meant i^8 ?
is that \(i^{18}\) ?
yes @r0n4ld
\[i^18=(i^2)^9=1^9=1\]
yayyyy i was right
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thanks guys you rock my socks
\[i^{18}=i^2 \cdot i^2 \cdot i^2 \cdot i^2 \cdot i^2 \cdot i^2\cdot i^2\cdot i^2\cdot i^2=(-1)^9=-1\] The answer is B
actually I did that wrong... it's -1.
\[i^{18} = (i^2)^9 = (-1)^9 = -1.\]
really? so i was wrong.
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are you sure?
Yes. Look at @r0n4ld or my calculation.
thanks!
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