Question

determine the local and/or absolute extrema of the function and where on the given interval they occur. g(x)=-x^2+12x-32 on [4,8]

Answer 1

either at \(g(4)\) or at \(g(8)\) or at \(g(6)\) that \(6\) being the first coordinate of the vertex

Answer 2

since it is symmetrical about the vertex \(g(4)\) should equal \(g(8)\) and that will be the min
max at the second coordinate of the vertex