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cos^x(sec^2x-1) what pythagoream identiy to use?
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first multiply them out. like a(b-c) = ab-ac so whats cos^x(sec^2x-1) = ... - ... ?
yeahhhhh right hartnn
cos^2x(sec^2x) - cos^2x-1
yup, and you know what cos x * sec x = .. ?
and -1 won't come.
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\(\large \cos^2x(\sec^2x-1)=\cos^2x\sec^2x-\cos^2x = ...?\)
can u simplify that ^ ? use the fact that cos x = 1/ sec x.
should i use factorization in this
nopes. since, cos x = 1/ sec x what is cos x * sec x = ... ?
should i turn secant into cos
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yes., do that...what u get ?
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