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Pre-Algebra
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decide whether the expression is positive, negative or 0. (-2) ^5power
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\[-2^{5}\]
=(-2)(-2)(-2)(-2)(-2) .... correct?
32
(-2)(-2) = 4 , agreed?
agreed
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that leaves 3 more -2's so (-2)(-2) = 4 again so now we have (4)(4) = 16, agreed?
agreed
so we have 1 (-2) left (-2)(32)=?
You can also remember that: 1) any negative number raised to an odd power will always be odd 2) any number (negative or positive) raised to an even power will always be positive.
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