Question

sec^2x-1/sin^2x

what does this match with?

sinxtanx or sec^2x

Answer 1

\[\frac{ sex ^{2}(x)-1 }{\sin ^{2}(x)}\]

Answer 2

correct?

Answer 3

yes sir

Answer 4

is there a trig rule with
\[\sec ^{2}(x)-1=?\]

Answer 5

yep the pythagoream identiy tan^2x + 1 = sec^2x

Answer 6

so then we would have:
\[\frac{ \tan ^{2}(x) }{ \sin ^{2}(x) }\]

Answer 7

yes n this is where im stuck

Answer 8

hmmmm
\[\tan ^{2}(x) = \frac{ \sin ^{2}(x) }{ \cos ^{2}(x) }\]

Answer 9

\[\frac{ \sin ^{2}(x) }{\cos ^{2}(x)} divided by \sin ^{2}(x)\]

Answer 10

Does that make sense?

Answer 11

not really :/

Answer 12

omg..everytime its a new way to find the answer how am i supposed to remember all of this???


and idk where to go from there

Answer 13

after you have to do it a few hundred/thousand times it finally starts to make sense.
PS - I use to (possibly still) despise Trig. So many rules and you have to see patterns and try to make sense of it.

Answer 14

and ......

Answer 15

I am in Calc I right now and it is a challenge with the Trig.

Answer 16

Still There?

Answer 17

thank you and yes i got it i had to look back up and figure out that first picture u drew for me made sense!!!

youre right, i wanna be a mechanical engineer so i better get used to this lol

Answer 18

1/cosx2 woulda been sec2x

Answer 19

haha, yes. How many semesters of math do you have?

Answer 20

Correct!

Answer 21

Lol i'm a senior and precalc is only a 2 semesters and i'm already on the second semester. my finals are next week and this is how far we got :( it was easy at first now its sooo hard