Algebra
23 Online
OpenStudy (anonymous):
find th maximum y-value on the graph on y=f(x). f(x)=-x^2+10x+3 the maximum y-value is y=
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OpenStudy (anonymous):
First, find derivative
OpenStudy (anonymous):
how do i do that?
OpenStudy (anonymous):
What course are you taking? what mrtods have you been using?
OpenStudy (anonymous):
Algebra 2
OpenStudy (anonymous):
are you able to help me
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OpenStudy (anonymous):
First find the x coordinate of the vertex\[\frac{ b }{ 2a }\]
OpenStudy (anonymous):
how do I do that
OpenStudy (anonymous):
\[ax ^{2}+bx+c=0\]
OpenStudy (anonymous):
okwhat do I do now
OpenStudy (anonymous):
\[-x^{2}+10x+3\]\[ax ^{2}+bx+c\]a=-1
b=10
c=3
Do you take notes in class?
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OpenStudy (anonymous):
yes I do take notes but having problems undertanding it, so what woud y=
OpenStudy (anonymous):
So you find x-coodinate of the vertex\[\frac{ b }{ 2a }\]
OpenStudy (anonymous):
10*2
OpenStudy (anonymous):
Take it one step at a time. Just plug in the values in \[\frac{ b }{ 2a }\]
OpenStudy (anonymous):
do not understand
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OpenStudy (anonymous):
Just read above, I told you what is a, what is b. Just put the values of a and b in\[\frac{ b }{ 2a }\]
OpenStudy (anonymous):
b is 10 anda s 1
OpenStudy (anonymous):
You put it in the expression\[\frac{ 10 }{ 2(-1) }\]
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
what do i do nxt
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OpenStudy (anonymous):
That expression simplifies to a number. You need to get that number.
OpenStudy (anonymous):
can you tell mehow to simplifies te exprsson
OpenStudy (anonymous):
would it be 5
OpenStudy (anonymous):
You need one-on-one time with your teacher or a tutor. Print out these messages and tell them you are having trouble following.
OpenStudy (anonymous):
wtever guess you cannot hep me
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OpenStudy (anonymous):
I did cotact a tutor and they s nt helpful