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please solve using quadratic formula: 2r^2=9r+81
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Write the quadratic formula here
-b±√ ̅ b^2-4ac _______________ 2a
apply the formula, and write what you got
1) -9±√ ̅ 9^2-4*2*81 _______________ 2*2 2)-9±√ ̅ 12474 _______________ 4 but then i get a realy big decimal
what am i doing wrong?
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here is your mistake.. Make the equation =0 not as it is now. This will give you the equation.... \[2r^2-9r-81=0\] from here do the formula. \[\frac{ 9\pm \sqrt{(-9)^2-4(2)(-81)}}{ 4} \] \[\frac{ 9\pm \sqrt{729} }{ 4 }\] \[=\frac{ 9\pm27 }{ 4}\]
ooooohh duhh stupid mistake lol thank you so much!!
no problem
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