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\[10x^{2} = 490\] Please show me step by step how to solve, so i can understand how you got the answer.
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divide both sides by 10 to get x^2 = 49
I'm sure you can see the answer from here
Dividing a number that ends in zero by 10 is easy, just drop the last zero. So 490 divided by 10 is 49. Now we have "x squared = 49" So list your perfect squares... 1 squared = 1 2 squared = 4 3 squared = 9 4 squared = 16 etc... You'll soon get to 49. But remember that (-3)*(-3) also equals nine... so you have TWO answers (one positive and one negative).
ty mathteacher1729
You're welcome. :)
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