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What is the sum of the first 30 terms of the series made from the sequence in 0.3, 0.1, 0? Find the 40th term of the sequence 3, 6, 9,....?
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The 40th term of the sequence is 120...since it goes up by 3 each time. 40(3)=120
ok..what about number 1?
looks like an arithmetic series with d = -0.2 a = 0.3 and n = 30 just substitute into the formula \[S_{30} = \frac{n}{2}[ 2a + (n -1)d]\] and evaluate
the 2nd question also appears to be arithmetic a = 3, d = 3 and n = 40 use the formula \[T_{40} = a + (n -1) d\]
30/2 [2(0.3)+(30-1)-0.2 ? @campbell_st
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not quite its \[S_{30} = \frac{30}{2}[2\times 0.3 + (30 - 1) \times (- 0.2)]\]
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