OpenStudy (anonymous):

need help finding the inverse of this equation: sqrt ( x^2 +5x)

5 years ago
OpenStudy (anonymous):

$\sqrt{x^2+5x}$ need to find inverse of that

5 years ago
OpenStudy (anonymous):

so first I do x= $\sqrt{y^2+5y}$

5 years ago
OpenStudy (anonymous):

then $x^2 = y^2 + 5y$

5 years ago
OpenStudy (anonymous):

but then I get confused about what to do next

5 years ago
OpenStudy (anonymous):

yeah..i really dont know how to do this lol.

5 years ago
OpenStudy (anonymous):

yeh thats ur inverse u got it man

5 years ago
OpenStudy (anonymous):

But that's not the answer my textbook has at all. My textbook somehow gets it down to a y = equation

5 years ago
OpenStudy (anonymous):

it's solution says $-\frac{ 5 }{ 2 } + \sqrt{x^2 + (\frac{ 5 }{ 2 })^2}$

5 years ago
OpenStudy (anonymous):

both are same actually

5 years ago