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64x^3+8=0 I know what the answers SHOULD be, I'm just so confused how to get there.
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huh?
are you asked to solve for x or expand?
isn't it the sum of a square but in cubic form so you have 4x and 2 and then you get (4x+2) = 0 and (4x^2+8x+4)
i'm having trouble when using the quadratic formula because i get that x = -1/2 (right) and x=-1 which is wrong.....
you're just asked to solve for x it looks like.. that's pretty easy
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subtract 8 from both sides and divide both sides by 64
x^3 = -1/8
take the cube root of both sides x=-1/2
i already got that part, i need the other two x's
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