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Calculus1
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Integral of an absolute value function?
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\[\int\limits_{0}^{3} \left| 2x-3 \right| dx\]
divide 2 cases : case I : calculate of int -(2x-3)dx [0,3/2] case II : calculate of int (2x-3)dx [3/2,3]
oh ok thanks. i can do the rest.
ok, welcome
wait sorry, why is it 3/2 ?
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first, u have to figure out the graph of y=2x-3, can u ?
nvm i got it.
great :*
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