Question

What is the vertex of the graph of::

Y=-x^2+4x-3

Answer 1

derive the equation
Y'=-2x+4
find critical numbers by setting derivative equal to 0
-2x+4=0
x=2
plug critical number into original equation to find vertex (maximum)
y(2)=-(2)^2+4(2)-3
y(2)=1
vertex is at (2,1)