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what is the square by square root of x2-4x=0
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\[x ^{2}-4x = 0\] ?
yes
\[(x+2\sqrt{x})(x-2\sqrt{x})\]
I'm guessing this is what your looking for?
well yes but in a different method like x2-32=0 x=addtion and subtraction4 root of2
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you lost me there
hold on
\(x^2-4x=0\iff x(x-4)=0\implies x=0\) or \(x=4\)
ah ok that makes sense. He wants to find the roots
yes that too but, :( its not the one im looking for'
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\[x^{2}-144=0\} \[x^{2}=144\rightarrow \sqrt{x}=\pm \sqrt{144}\rightarrow \alpha =\pm12\]
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