If ABC (triangle) B is a right angle, and sinB = 3/5. Find cos B, cot B and sin C in fraction form. How would I figure this out? I will draw an image to help.

Question

If ABC (triangle)  B is a right angle, and sinB = 3/5. Find cos B, cot B and sin C in fraction form. How would I figure this out? I will draw an image to help.

anonymous · Answer

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anonymous · Answer

@Agent_Sniffles

anonymous · Answer

@Harkirat

anonymous · Answer

@phi

anonymous · Answer

cos B would be adj/hypo 
so cos 90 = sidec/5

anonymous · Answer

isolate sidec  which would b c=5cos90,

anonymous · Answer

I absolutely hate trig, everytime I start understanding it, It looses me completely. Thank you so much.

phi · Answer

***I absolutely hate trig, everytime I start understanding it, It looses me completely. *** then watch the first few videos over and over until it sinks in (It will) http://www.khanacademy.org/math/trigonometry (New ideas sometimes make no sense, but then it "clicks" )