Question

solve: x^4 - 18^2+32=0

Answer 1

18^2 or 18x^2 ?

Answer 2

it would only make sense if it were 18x^2
so...
(x^2-16)(x^2-2) = 0
x = +/- 4. sqrt(2)

Answer 3

18x^2

Answer 4

@jennychan12 thanks so much but I have one more Question 8x^3 - 27=0

Answer 5

8x^3 = 27
x^3 = 27/8
x = \[\sqrt[3]{\frac{ 27 }{ 8 }}\]

Answer 6

thanks