Question

relative extrema of f(x)=x^3-3x+6

Answer 1

first derivative, sign chart

Answer 2

3x^2-3

Answer 3

find the derivative of the function then set that equal to 0 and solve for x
these x values will give you your critical points
plug the critical points back into you original equation and solve
the greatest value you get is your relative maximum and the smallest value you get is your relative minimum
does that help?

Answer 4

yes thank you very much!

Answer 5

np