Question

Find the General solution of\[tanx + \tan(x+60) + \tan(x+120) = 3\]

Answer 1

i think we can use identity :
tan(A+B) = (tanA +tanB)/(1-tanAtanB)
to simplify of tan(x+60) and tan(x+120)

Answer 2

But it will end up in

tan^3 x - 3tan^2 x - 3tan x + 1=0

Answer 3

yes, factor out to get
(tanx+1)(tan^2 x -4tanx + 1) = 0

Answer 4

got..it thaxxx

Answer 5

for zeros, tanx = -1
so on ..... bla bla :)

Answer 6

welcome