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OpenStudy (anonymous):
AP Calculus: A cylindrical can is to hold a volume of 800cc. The can has double thick top. Find the dimensions to use the minimum surface area.
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OpenStudy (anonymous):
so far I have S=3pir^2+2pirh 800=pir^2h, h=800/pir^2 S=3pir^2+2pir(800/pir^2) S=3pir^2+1600/r S'=6pir+-1600/r^2=0
OpenStudy (anonymous):
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