Question

Solve algebraically: log15 + log(2x-3) - log2= 1/6

Answer 1

use log properties
log15+log(2x-3)=log(30x-45)

Answer 2

You can then do
log((30x-45)/2)
= log(15x-45/2)=1/6
Raise both sides to the tenth to get rid of the log
15x-45/2=10^(1/6)

Answer 3

thank you!