Question

Please help! D:

Solve the simultaneous equations 64(4^y) = 16^x and 3^y = 4(3^x-2) - 1

Answer 1

put ln and slove lol im too lazy to write all this ._.

Answer 2

@ The problem is I tried but after I reached 3^y = 4(3^x-2) - 1 I did not know what to do

Answer 3

@masterxnonos

Answer 4

It is supposed to be question with solving by appropriate substitution and indices