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Please help! D: Solve the simultaneous equations 64(4^y) = 16^x and 3^y = 4(3^x-2) - 1
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put ln and slove lol im too lazy to write all this ._.
@ The problem is I tried but after I reached 3^y = 4(3^x-2) - 1 I did not know what to do
@masterxnonos
It is supposed to be question with solving by appropriate substitution and indices
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