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When approximating the square root of 2 by applying Newton's Method, is the answer (+-)1.4142 or just positive 1.4142?
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generally Newton's method will give you one of the roots, but the other one is the negative of the one found.
I would define this function: f(x) = x²-2. Differentiating gives f'(x) = 2x. Newtons method:\[x _{n+1}=\frac{ x _{n}^{2}+2 }{ 2x _{n} }\] Starting with a positive number for x0, will lead you to 1.4142... A negative start value goes to -1.4142... See attached img
Ok, so (+-)1.4142 is a suitable answer to the problem
Yes, it is.
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