Question

Is anyone good with trigonometry?

Answer 1

I'm free to help

Answer 2

ok thank you ok soo i need help with writeing ratioes foe sin x, cos x ,
tan x

Answer 3

I dont quite understand what you mean

Answer 4

well, if o = the side opposite to the angle, h = the hypotenuse, and a = the side adjacent to the angle,

sinθ = o/h
cosθ = a/h
tanθ = o/h

Answer 5

\[\boxed{\sin(\theta)=\dfrac{\text{opposite side}}{\text{hypotenuse}}}\]\[\boxed{\cos(\theta)=\dfrac{\text{adjacent side}}{\text{hypotenuse}}}\]\[\boxed{\tan(\theta)=\dfrac{\sin(\theta)}{\cos(\theta)}=\dfrac{\text{opposite side}}{\text{adjacent side}}}\]

Answer 6

ya like ik dat bt lyke im tryna set it up n idk hw to du dat

Answer 7

if we are looking at angle x

sin (x)=12/13