What are the three consecutive odd integers of:
x + (x+2) + (x+4) = 537

A. 177, 178, 179
B. 177, 179, 181
C. 181, 182, 183
D.181, 183, 185

Question

What are the three consecutive odd integers of: 
x + (x+2) + (x+4) = 537

A. 177, 178, 179
B. 177, 179, 181
C. 181, 182, 183
D.181, 183, 185

zepdrix · Answer

X represents the FIRST of the three odd integers. So simply solve for X, and you will have found the first odd number. The next number will be 2 MORE than X as described by the (x+2).

$$\large x+(x+2)+(x+4)=537 \quad \rightarrow \quad x+x+2+x+4=537$$$$\large 3x+6=537$$Understand how I combined the x's?