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find the exact value if angles x and y are in the first quadrant. tan(x+y) if cotx=6/5 and secy=3/2
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tan(x+y) = (tanx+tany)/(1-tanxtany) u have to determine the values of tanx and tan y to complete it in the formula
i have that tanx(5/6) and tany(sqrt5/2)
good, just plug of them to formula above
so I dont need to ise the sum formula?
simplify it
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but im not getting the same answer when i check the answer
what ur answer did u get
(5+6sqrt5)/(6-5sqrt5)
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