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the product of three intergers is 90. the second number is twice the first number. the third number is two more then the first number. what are the three numbers
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1st number: n 2nd number: 2n 3rd number: 2+n Product: 90
ok
i know this part but not how to slove
Ohh, ok. SO, foil (n)(2n)(2+n).
what do i do after 2x^3+4x^2-90=0
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I would divide by 2 just to simplify a bit.
can u show me how
|dw:1355280000958:dw|
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