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Compute the following binomial probabilities directly from the formula for b(x; n, p). (a) b(1; 6, 0.43) (b) b(1; 7, 0.77) (c) P(3 X 5) when n = 9 and p = 0.69 (d) P(1 X) when n = 9 and p = 0.21
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try urself with prob=C(n,x) * (p^x) * (1-p)^(n-x) for a) it is C(6,1) * (0.43)^1 *(1-0.43)^(6-1)
i hope rest u will be able to do as just u hv to plug in for x,n and p
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