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Special Quadratic Equation I don't understand them
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which equation ?
can u be more specific ?
x^2-64=0 i have to find out another way to make it true
whats the first way ?
x= -b(-+)(square route)b (squared )- 4 ac (divided by a)
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8^2-64=0
x^2-64 =0 you can take 64 to other side x^2 =64 then take square root on both side, what u get ?
I dont understand..
\[x = -b \pm \sqrt{?} ^{b}-4ac \ \div 2a\]
thats the quodratic equation
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