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help me if x is the random variable such that E(x)=2.4,P=0.6,find the value of n and standard deviation
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is \(X\) binomial?
yes
binomial
\[E[X]=np\] so \[np=2.4\] and \[n=\frac{2.4}{p}\] plug in your value of \(p\)
\[Var[X]=npq\] so \[Sd[X]=\sqrt{npq}\] where \(q=1-p\)
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thankx much in deed
no problem
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