Question

The derivative of the function f is given by f'(x)= x^2cos(x^2). How many points of inflection does the graph of f have on the open interval (-2,2)?

Answer 1

To find possible inflection points, you must find the second derivative and set it equal to 0.

Answer 2

I get that, I'm having trouble figuring out the second deriv.

Answer 3

2x⋅cos(x2)−2x3⋅sin(x2)

Answer 4

Ah thank you!

Answer 5

You're welcome.