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How does (2CosX-1)(CosX-3)=0
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This question would be better phrased as when does (2CosX-1)(CosX-3)=0. Regardless you can multiply out to get 2cos^2(x)-6cosx-cosx+3=0 => 2cos^2(x)-7cosx=-3. from there, you can either use acos or use unit circle. knowing cos(pi/3)=1/2, 2(1/4)-7/2=-6/2 or -3. so pi/3 is what your answer is.
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