Question

square root of 45x^3y

Answer 1

\[45=9\times 5\] so \(\sqrt{45}=\sqrt{9\times 5}=\sqrt{9}\times \sqrt{5}=3\sqrt{5}\) is a start

Answer 2

also \(\sqrt{x^3}=\sqrt{x^2}\times \sqrt{x}=x\sqrt{x}\)

Answer 3

so a \(3\) comes out of the radical, a \(x\) comes outside, and the \(5xy\) stays inside, giving
\[3x\sqrt{5xy}\]

Answer 4

can u help with the whole problem? its √45x^3y - √20xy/ √2xy