Question

Factor the trinomial by grouping. 8y^2-18y+10

Answer 1

2(y-1)(4y-5)

Answer 2

8*10=80
8y^2-18y+10 ---> 8y^2-8y-10y+10
8y(y-1)+ -10(y-1) ----> (8y-10)(y-1)

Answer 3

Factor out the 2
2(4y-5)(y-1)
There really isn't a way to learn this without just looking at examples. http://www.mathwarehouse.com/algebra/polynomial/how-to-factor-by-grouping.php

Answer 4

thank you! :)