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The sum of a number and twice its reciprocal is 27/5. find the number
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x + 2(1/x) = 27/5
okay but then what?
and is it 1/x because thats the reciprocal?
ya
so then x + 2/x + 27/5
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= 27/5
multiply everything by x to get rid of the fraction. x^2 + 2 = 27/5x
5x^2 -27x + 10 =0
then factor to solve it i guess or use the quadratic formula. I am not 100% sure of this, double check or see if the answer u get is correct
idk how to factor that. i cant do it
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idk i guess thats the only way to do it
(5z-2)(z-5)=0
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