Question

mean value theory problem help. see picture.

Answer 1

the eqn of secant ;line is
(y-f(a))=m(x-a) where m is=(f(b)-f(a))/(b-a)

Answer 2

thank you so much.

Answer 3

hey wait ur problem is not complete

Answer 4

u have find a tangent line also for that just diff the curves and put them in place of m

Answer 5

i have f(.5)=2.5
f(2)=2.5
for #9

Answer 6

ys they u r doing it correctly

Answer 7

i don't know what to do after that. that's all i figured out

Answer 8

now put them in this format
(y-f(a))=m(x-a) where m is=(f(b)-f(a))/(b-a

Answer 9

\[m= \frac{ 2.5-2.5 }{ 2-.5 }= 0\]
\[y-2.5=0(x-.5)\]

Answer 10

is that correct?

Answer 11

@RajshikharGupta ?

Answer 12

yes