Question

solvign using complete the square: 2x^2-4x-8=0

Answer 1

Take the 2 out first

2(x^2-2x-4)=0

2(x^2-2x+1-1-4)=0
2((x-1)^2-5)=0
2(x-1)^2-10=0
2(x-1)^2=10
(x-1)^2=5

Can you handle the rest?

Answer 2

yes thanks!!!!

Answer 3

wait where did you get the +1-1 in the second step?

Answer 4

coefficient of x divided by 2 then squared

(-2/2)^2=1 you add and subtract that after x

Answer 5

oh okay thanks!