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If f(x)=(x-a)(x-b) ,find the value of x for which f'(x)=0
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\[\LARGE f'(x)=2x-a-b\]
i have to equate it to 0?
2x=a+b
yes
x=..?
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x=a+b/2?
yup, don't forget to put brackets (a+b)/2
yes..is that it? seriously :P
yup.
alright!
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