Question

3x^2+18=0

10x^2-11x-6=0

Answer 1

3x^2 + 18 = 0
3(x^2 + 6) = 0
x^2 + 6 = 0
x^2 = -6
x = ±sqrt(-6)
x = ±sqrt(6)i

Answer 2

For the second problem, use quadratic formula

a = 10, b = -11, c = -6

\[x = \frac{-b ±\sqrt{b^2 - 4ac}}{2a}\]